Jika f(x)=ax + 6
f(1)=8 dan f(-1)=2
Tentukan f(4)
Pakai cara
f(1)=8 dan f(-1)=2
Tentukan f(4)
Pakai cara
Materi : Fungsi dan Relasi
f(1) = 8 => a + b = 8
f(-1) = 2 => - a + b = 2
Metode Eliminasi ( b )
a - ( - a ) = 8 - 2
a + a = 6
2a = 6
[ a = 3 ]
a + b = 8
b + 3 = 8
b = 8 - 3
[ b = 5 ]
Hasil / Result :
{ a = 3 dan b = 5 }
Bentuk Fungsi : f(x) = 3x + 5
Nilai f(4) = 3(4) + 5 = 12 + 5 = 17
Semoga bisa membantu
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